For the math/statistics and science minded.....
I have chemistry lab values (Kc / Keq values) that have an average of 212 for an experiment that have a standard deviation of 1.37; when I take the standard deviation divided by the average x 100, (1.37/212 x 100) I get .6% is how off I am, which is not good I know but I know where I went wrong. What I cannot remember is where from these figures, how to I get the experimental variance of +/- a number for the average 212 +/- ?. Can anyone help by chance? I know it's right in front of me but I am drawing a complete blank and what I have found online is not helping. I will continue to search meanwhile. Thanks in advance for your help.