[hopealwayz]

It's hard going into a therapeutic relationship with the knowledge of it ending in the future. It's like knowing that you're going to end up getting hurt one day. What makes it worth it?

[ADeepSandbox]

I think you can say the same about anything, really. I struggle with that too. Nothing lasts forever. Most people seem to live more in the moment and take things in stride. But when you've been through really painful partings, it does make you question why it's worth it.

Honestly? I think it's up to you to answer your question, because only you know deep down why you're trying despite inevitable pain. There must be something inside you that keeps hoping things can get better, even if it's very tiny. Like a single thread. But it's there. I think that matters a lot. It says that there can be good things too, and pain doesn't last forever.

It's a struggle though, and I wish you the best in trying to find your answers.

[growlycat]

There are good endings not just bad ones. There are endings where it s your choice for positive reasons. There are some endings where the door is still open. It doesn't have to be crushingly painful.

[ruh roh]

Originally Posted by hopealwayz

What makes it worth it?

Getting better makes it worth it (or whatever one's goal is for going).

[awkwardlyyours]

What makes it worth it?

The fact that it'll end.

[atisketatasket]

Originally Posted by awkwardlyyours

What makes it worth it?

The fact that it'll end.

Exactly. You go through the process, you heal or grow or whatever you call it, you stand on your own two feet, you walk out the door into a new life, or a better one at least.

It's not meant to be a friendship or a partnership that lasts without any limits on it.

[junkDNA]

i guess im like ruh roh... my goal is to get better. i love my T but being with him forever isnt my goal. my goal is to be ok with saying goodbye to him and living my life fully

[stopdog]

I don't know - I keep getting pets knowing I will outlive them. And I get very very attached to my animals.