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#1
Jun 18, 2011, 04:56 PM
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For the math/statistics and science minded.....
I have chemistry lab values (Kc / Keq values) that have an average of 212 for an experiment that have a standard deviation of 1.37; when I take the standard deviation divided by the average x 100, (1.37/212 x 100) I get .6% is how off I am, which is not good I know but I know where I went wrong. What I cannot remember is where from these figures, how to I get the experimental variance of +/- a number for the average 212 +/- ?. Can anyone help by chance? I know it's right in front of me but I am drawing a complete blank and what I have found online is not helping. I will continue to search meanwhile. Thanks in advance for your help. 
__________________
 I can be changed by what happens to me. But I refuse to be reduced by it. -M.Angelou Life shrinks or expands in proportion to one's courage. -Anaïs Nin. It is very rare or almost impossible that an event can be negative from all points of view. -Dalai Lama XIV |
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#2
Jun 19, 2011, 02:12 AM
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Isn't varience standard deviation squared?
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 Fresia
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